Re: String literals and templates

From:
"Matthias Hofmann" <hofmann@anvil-soft.com>
Newsgroups:
comp.lang.c++.moderated
Date:
17 Aug 2006 07:39:00 -0400
Message-ID:
<4kj05mFcc4b3U1@individual.net>
"James Hopkin" <tasjaevan@gmail.com> schrieb im Newsbeitrag
news:1155728486.620963.86200@m73g2000cwd.googlegroups.com...

Aaron Graham wrote:

template <typename T, typename U, typename V>
void foo(const T& t, const U& u, const V& v);

Now, to provide an equivalent solution for this one, I would need to
define 7 more overloaded functions.


You can do it with a single forwarding function like this:

 #include <cstddef> // for size_t

 template <typename T>
 struct Param { typedef T type; };

 template <typename T, std::size_t N>
 struct Param<T[N]> { typedef const T* type; };

 template <typename T, typename U, typename V>
 void foo_impl(const T& t, const U& u, const V& v)
 {
 }

 template <typename T, typename U, typename V>
 void foo(const T& t, const U& u, const V& v)
 {
     foo_impl(
       static_cast<typename Param<T>::type>(t),
       static_cast<typename Param<U>::type>(u),
       static_cast<typename Param<V>::type>(v) );
 }

Note that if any of foo's parameters need to be non-const-qualified
references (i.e. so that const-ness is deduced from the parameter
coming in), a little more work is needed.


Am I right in thinking that a static_cast may cause a temporary to be
constructed? What about the following alternative definition of struct
Param<> to prevent this:

template <typename T>
struct Param { typedef const T& type; };

--
Matthias Hofmann
Anvil-Soft, CEO
http://www.anvil-soft.com - The Creators of Toilet Tycoon
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