=?windows-1252?Q?Re=3A_error=3A_expected_primary=2Dexpression_before_=91int?= =?windows-1252?Q?'?=

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sat, 1 Nov 2008 15:44:14 CST
Message-ID:
<a346c9db-0f15-4f4a-a14a-9149f33ea1f3@p10g2000prf.googlegroups.com>
On 1 Nov., 16:58, raikanta.s...@gmail.com wrote:

Can somebody please explain why I am getting a compiler error when
compile the following block of code using g++ under Ubuntu 8.04? Thank
you.

template <typename T1>
class AA
{
   public:
      AA(){};
      template <typename T2>
         T2 const& get()
      {
         static T2 item;
         return item;
      }

   private:

      T1 x;

};

template <typename T1>
void testAA()
{
   AA<T1> aa;
   int i = aa.get<int>();

}

template <>
void testAA<int>()
{
   AA<int> aa;
   double d = aa.get<double>();

}

void test()
{
   testAA<int>();
   testAA<double>();

}


You need to insert the keyword 'template' at
the point where the primary function template
testAA() accesses get:

    int i = aa.template get<int>();

This is necessary, because aa depends via
AA<T1> on the template parameter T1. Thus the
compiler cannot guarantee that get is a
(template) member function or not (A specialization
could define it as something different).
Under these conditions the occurrence of '<'
after get is interpreted as operator<, which
shortly later causes a conflict with 'int'.
This usage of 'template' is the correspondence of
the need to use 'typename' in other depending
expressions where the compiler cannot deduce whether
something is a type or not, e.g. in

template <class T>
std::vector<T>::iterator foo();

which needs to be adapted to

template <class T>
typename std::vector<T>::iterator foo();

HTH & Greetings from Bremen,

Daniel Kr?gler

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