Re: Trick to prevent conversion

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Fri, 11 Jan 2008 16:22:39 -0500
Message-ID:
<fm8mn0$8gr$1@news.datemas.de>
Tom1s # hilidhe wrote:

(I'm simplifying this problem greaty in the following code but you get
the idea)

I have a class something like:

class Processor {
public:
   unsigned GetCurrentProcess(void);
   unsigned GetCurrentThread(void);


If you can, perhaps you would get in the habit of omitting 'void'
for a function with no arguments. I know I'd appreciate it because
your code would be easier to read and understand.

Also, it seems that those functions should perhaps be 'const'. If
they don't change anything in 'Processor', of course.

   void DoSomethingWithProcess(unsigned process_id);
   void DoSomethingWithThread(unsigned thread_id);
};

   The function, GetCurrentProcess, returns an unsigned integer value
which represents a process.
   The function, GetCurrentThread, returns an unsigned integer value
which represents a thread.

The problem is, that it's very easy to mistakenly take the value from
GetCurrentProcess and pass it as an argument to DoSomethingWithThread.
(I've done it already!). Therefore, I want two different types for
these identifiers, two types that can't convert to each other. At the
moment I have the following:

class Processor {
public:

   struct ProcessHandle { unsigned i; };
   struct ThreadHandle { unsigned i; };

   ProcessHandle GetCurrentProcess(void);
   ThreadHandle GetCurrentThread(void);

   void DoSomethingWithProcess(ProcessHandle process_id);
   void DoSomethingWithThread(ThreadHandle thread_id);
};

Of course, this does the trick. But I'm wondering if there's a more
elegant way of doing it? What other methods are there for making types
incompatible with each other?


Enums.

(My actual code is far more complicated than this -- obviously I
wouldn't be very competant if I made such a stupid mistake in code as
simple as this).


V
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