Re: [Threading to manage simulated printing jobs]

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 09 Sep 2007 14:33:39 -0400
Message-ID:
<wMOdnZrph4MeoXnbnZ2dnUVZ_uWlnZ2d@comcast.com>
getsanjay.sharma@gmail.com wrote:

Hello to all Javascript programmers out there. :)


Wrong group. They won't be listening here.

I am really ashamed to say that even after 6 months of intermittent
Java programming I have been a complete failure at grasping the
concepts or the real thing behind 'threading'.


Join the crowd. Nearly all Java programmers have yet to grok threading.

class Consumer {
    private static int gId;

Accessed by many threads, yet you don't synchronize those accesses. Not safe.

Do not use TAB characters in Usenet posts.

  private PrintQueue queue;

  private String id;

  private Consumer() {
  }


You do not need this constructor. Also, it's conventional to place all
constructor definitions together.

  private Runnable job = new Runnable() {
    public void run() {
      // start consuming the print jobs and print them
      try {
        for (;;) {
          //System.out.println("Inside run of producer");


Use logging, not System.out.println(). And isn't this the consumer?

          Thread.sleep(10);
          PrintJob job = queue.getJob();


You'd better make sure the queue is synchronized!

          if (job != null)
            System.out.println(id + job.print());


Use logging, not System.out.println(). And you forgot your braces.

        }
      } catch (Exception e) {
        e.printStackTrace();
      }
    }
  };

  public Consumer(PrintQueue queue) throws Exception {
    this.queue = queue;
    this.id = "Consumer" + gId;
    gId++;


Synchronize!

    Thread t = new Thread(job);
    t.join(); /* Does this even do anything? */


Have you read the Javadocs on Thread.join?
<http://java.sun.com/javase/6/docs/api/java/lang/Thread.html#join()>
It causes the current thread to wait for the target thread to finish. Of
course, in your case it hasn't started yet.

    t.start();


I am thinking it's a bad idea to fire off threads or do any significant work
in the constructor.

  }
}


Buy and study /Java Concurrency in Practice/ by Brian Goetz, et al.

--
Lew

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