Re: About list::sort() in STL

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 24 Oct 2007 18:51:46 GMT
Message-ID:
<6vMTi.12115$ZA.7890@newsb.telia.net>
On 2007-10-24 20:11, gjin@mail.utexas.edu wrote:

On Oct 24, 12:35 pm, red floyd <no.s...@here.dude> wrote:

g...@mail.utexas.edu wrote:

Hi there,

    I met a problem, which I could not solve. I used it as the
following:

list<long> L

for (long i=1;i<=479250; i++)
L.push_back(i);

L.size(); // this gives 479250;

L.sort();

L.size(); // Here it gives 20498?

Why the elements in the list are removed??? I could not understand it

Really appreciate your help!


Doesn't happen in g++ 3.4.4. What is your platform? Please provide a
minimal *COMPILABLE* (emphasis on compilable) example that exhibits the
behavior in question.

Thank you.- Hide quoted text -

- Show quoted text -


I use Visual C++ 6.0. Here is a simple example I test, which does not
work.

#include <iostream>
#includer<list>

using namespace std;

int main()
{

   list<long> L;

   for (long i=1;i<=479250; i++)
      L.push_back(i);

    cout<< L.size()<<endl; // give 479250

    L.sort();

    cout<< L.size() << endl; // give 20498;???

    return 0;
}


Not reproducible in VC++ 2005, seems like an implementation bug to me.

--
Erik Wikstr??m

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