Re: About list::sort() in STL
On 2007-10-24 21:11, gjin@mail.utexas.edu wrote:
On Oct 24, 1:51 pm, Erik Wikstr??m <Erik-wikst...@telia.com> wrote:
On 2007-10-24 20:11, g...@mail.utexas.edu wrote:
On Oct 24, 12:35 pm, red floyd <no.s...@here.dude> wrote:
g...@mail.utexas.edu wrote:
Hi there,
I met a problem, which I could not solve. I used it as the
following:
list<long> L
for (long i=1;i<=479250; i++)
L.push_back(i);
L.size(); // this gives 479250;
L.sort();
L.size(); // Here it gives 20498?
Why the elements in the list are removed??? I could not understand it
Really appreciate your help!
Doesn't happen in g++ 3.4.4. What is your platform? Please provide a
minimal *COMPILABLE* (emphasis on compilable) example that exhibits the
behavior in question.
Thank you.- Hide quoted text -
- Show quoted text -
I use Visual C++ 6.0. Here is a simple example I test, which does not
work.
#include <iostream>
#includer<list>
using namespace std;
int main()
{
list<long> L;
for (long i=1;i<=479250; i++)
L.push_back(i);
cout<< L.size()<<endl; // give 479250
L.sort();
cout<< L.size() << endl; // give 20498;???
return 0;
}
Not reproducible in VC++ 2005, seems like an implementation bug to me.
--
Erik Wikstr??m- Hide quoted text -
Please do not quote signatures.
About red floyd reply:
Yes, I used the above code to test exactly on my computer. I got wrong
result.
I guess it was caused by my visual C++ 6.00 or Standard Template
Library
Does anyone use visual C++ 6.00 and can help test it?
About Erik's reply:
Does you mean that my test code works well in your Visual C++ 2005?
Yes, it works just fine for me.
--
Erik Wikstr??m
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