Re: Using std::less_equl predicate with std::min()

From:
"Igor Tandetnik" <itandetnik@mvps.org>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 12 Jan 2010 09:01:01 -0500
Message-ID:
<#szEw#4kKHA.5604@TK2MSFTNGP04.phx.gbl>
Vladimir Grigoriev wrote:

int a[] = { 6, 1, 7, 1, 8 };
int *p = std::min_element( a, a + sizeof( a ) / sizeof( *a ),
                                               std::less_equal() );

 
Use a reverse iterator to search from the end. All search functions =

return

the first match, not the last.
 

 
How to use reverse iterators with arrays?


typedef std::reverse_iterator<int*> rev_it;
int a[] = { 6, 1, 7, 1, 8 };
int *p = std::min_element(
    rev_it(a + sizeof( a ) / sizeof( *a )), rev_it(a), std::less() =
).base();

Nope, the strict ordering comes from the C++ standard which in turn =

took

it
from the STL. You're barking up the wrong tree. BTW: I'd ask this on
comp.lang.c++.moderated, you have typically more C++ experts there.

 
Yes, I do not know the standard


You can get a copy of C++98 here:

http://www-d0.fnal.gov/~dladams/cxx_standard.pdf

C++03 here:
http://openassist.googlecode.com/files/C%2B%2B%20Standard%20-%20ANSI%20IS=
O%20IEC%2014882%202003.pdf

and the most recent draft of C++0x here:

http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2009/n3000.pdf

but I think that strict ordering requirments
is applied not to all algorithms.


Perhaps, but it does apply to std::min and std::min_element.
--
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    Igor Tandetnik

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