Re: Length of C++ arrays allocated by operator new[]

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
22 Aug 2011 06:06:42 GMT
Message-ID:
<4e51f1f2$0$2861$7b1e8fa0@news.nbl.fi>
Marcel M?ller <news.5.maazl@spamgourmet.org> wrote:

- STL causes the executable size to explode. One disadvantage of
template meta programming over generics.


  Why is this urban legend so persistent? People repeat it without actually
trying it.

  I just tested with these two programs:

//---------------------------------------------------------
int main()
{
    int* array = new int[10000];
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    delete[] array;
    return value;
}
//---------------------------------------------------------

//---------------------------------------------------------
#include <vector>

int main()
{
    std::vector<int> array(10000);
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    return value;
}
//---------------------------------------------------------

  The size of the first executable? 5104 bytes.
  The size of the second executable? 5528 bytes.

  Yeah, the size really exploded.

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