Re: Length of C++ arrays allocated by operator new[]

From:
=?ISO-8859-15?Q?Marcel_M=FCller?= <news.5.maazl@spamgourmet.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 22 Aug 2011 09:19:00 +0200
Message-ID:
<4e5202e6$0$6638$9b4e6d93@newsspool2.arcor-online.net>
Juha Nieminen wrote:

Marcel M?ller <news.5.maazl@spamgourmet.org> wrote:

- STL causes the executable size to explode. One disadvantage of
template meta programming over generics.


  Why is this urban legend so persistent? People repeat it without actually
trying it.

  I just tested with these two programs:

//---------------------------------------------------------
int main()
{
    int* array = new int[10000];
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    delete[] array;
    return value;
}
//---------------------------------------------------------

//---------------------------------------------------------
#include <vector>

int main()
{
    std::vector<int> array(10000);
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    return value;
}
//---------------------------------------------------------

  The size of the first executable? 5104 bytes.
  The size of the second executable? 5528 bytes.

  Yeah, the size really exploded.


Use it for some dozen different types, not just int.
Use many functions of the STL containers not just the easiest ones.

Templates have to be instantiated for each unique parameter set. Even if
90% of the generated functions do not depend on all parameters or the
dependency ends once the compiler has done the type checks, the compiler
will generate distinct implementations. No programmer would repeat his
self that much without the templates (well, hopefully).

Marcel

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