Re: Does VC++ 6.0 support templates well?
On Feb 26, 2:42 am, "Harvey" <harve...@juno.com> wrote:
On Feb 26, 12:54 am, "xrxst32" <martin.dangelm...@dcx.com> wrote:
On Feb 25, 4:56 pm, "Harvey" <harve...@juno.com> wrote:
I am trying to get started on C++ templates.
I know I am behind the times, but I am trying to compile "Budget6"
from the book (and disk) "C++ for Dummies".
The compiler (VC++ 6.0 on Win98) gives me 102 errors.
First error:
c:\_\chap26\sll.h(12) : error C2059: syntax error : '<'
is on line indicated:
TIA,
Harvey
-------------------------------------------------------------
// (comment lines snipped)
template <class T> // Note 2
class SLLNode
{
friend class SLL<T>; //<------------------ error
protected:
SLLNode<T>(T* pD)
{
pNext = 0;
pData = pD;
}
SLLNode<T>* pNext; // pointer to next node // Note 3
T* pData; // pointer to data
};
// SLL - this class represents a single list class. // Note 2
// A singly linked list consists of a list of nodes
// each of which points to the data.
template <class T>
class SLL
{
protected:
SLLNode<T>* pFirst; // pointer to first node // Note 4
SLLNode<T>* pLast; // pointer to last node
SLLNode<T>* pCurrent; // pointer to "current" node
int nMembers; // number of members in list
public:
SLL();
// add - add member to end of list
void add(T* pData)
{
// create a node which points to our data
SLLNode<T>* pNode = new SLLNode<T>(pData); // Note 5
// add it to the end of the list
if (pLast)
{
pLast->pNext = pNode;
}
pLast = pNode;
// if this is the only member in the list...
if (pFirst == 0)
{
// ...make it first member also
pFirst = pNode;
}
// now count it
nMembers++;
}
// count - return the number of accounts
int count()
{
return nMembers;
}
// provide navigation functions
// current - return the data pointer of current node
T* current();
// over - move over to the next node
void over()
{
pCurrent = pCurrent->pNext;
}
// reset - reset to beginning of list
void reset()
{
pCurrent = pFirst;
}
};
// constructor - build an empty list
template <class T>
SLL<T>::SLL()
{
pFirst = pLast = (SLLNode<T>*)0;
pCurrent = (SLLNode<T>*)0;
nMembers = 0;
}
// current - return the data pointer of current node
template <class T>
T* SLL<T>::current()
{
// assume data pointer is zero...
T* pData = (T*)0;
// if we aren't off the end of list...
if (pCurrent)
{
// ...then replace with actual data ptr
pData = pCurrent->pData;
}
return pData;
}- Hide quoted text -
- Show quoted text -
Your code should look something like this then it will compile just
fine:
// forward declaration of template class SSL
template <class T> SSL;
template <class T>
class SSLNode
{
friend class SSL<T>;
...
};
template <class T>
class SSL
{
...
};
Well, the very first line now gives:
c:\_\lcw16.9\sll.h(10) : error C2501: 'SLL' : missing storage-class or
type specifiers
followed by 920 more errors.
I did get a much simpler template to work though, so I guess there is
hope.
Thanks MrAsm,
Harvey
Ok, got it to work with one more change. First line chaged from:
template <class T> SSL;
to:
template <class T> class SSL;
No errors now :)
Now to start using it... and modifying it...
Thank you much MrAsm.
Harvey
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