Re: How Does compiler implement virtual destructor ???

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
Wed, 16 Apr 2008 06:33:58 +0300
Message-ID:
<4805d3ce$0$8173$4f793bc4@news.tdc.fi>
Pallav singh wrote:

Hi All

How Does compiler implement virtual destructor ???

as we all know if base class destructor is virtual..........then while
wriiting statemnt like this

Base * b = new Derived( );
delete b;

// it will call Deived class destructor Followed by Base Class

How compiler does House-keeping for it in V-Table ??


  It's most probably again one thing which the standard doesn't specify,
but which all compilers do in the same way:

  If there exists any virtual functions in a class (eg. a virtual
destructor) the size of the class will be increased by a pointer.
Internally this pointer points to a virtual table which contains
pointers to the virtual functions at fixed offsets. When calling a
virtual function (eg. the destructor), what it actually does is that it
takes that pointer, indexes it with a fixed value, takes the function
pointer found there and calls that function. If it's a destructor, then
the destructor will call the destructor of its own base class, etc.

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