Re: How Does compiler implement virtual destructor ???

From:

James Kanze <james.kanze@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Wed, 16 Apr 2008 07:00:54 -0700 (PDT)

Message-ID:

<509d8238-370a-431c-a3af-97c1b5533cef@b1g2000hsg.googlegroups.com>

On Apr 16, 10:08 am, Michael DOUBEZ <michael.dou...@free.fr> wrote:

Pallav singh a =E9crit :

How Does compiler implement virtual destructor ???

as we all know if base class destructor is
virtual..........then while wriiting statemnt like this

Base * b = new Derived( );
delete b;

// it will call Deived class destructor Followed by Base Class

How compiler does House-keeping for it in V-Table ??

The destructor of the derived class will be called like any
other virtual function, that is why if you don't make it
virtual, you will not destroy the most derived object.

If you don't make it virtual, you'll have undefined behavior.
It might not destruct the most derived object, it might not free
the memory at all, it might crash, or it might cause a subtle
bug to appear later in your code.

--
James Kanze (GABI Software) email:james.kanze@gmail.com
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